Not suitable code Abigail Foy \"treasure map\" (Prey (2017))

That does not, the code is not found

Starkin
I mean not the same?)))

Ga M eR
1365 this,try it.

Ga M eR
The same thing was not one of those specified in the Internet did not work - then take it and move on obum, I spent 10-15 minutes until it worked, the campaign, the game randomly generates an individual code for each game. How many combinations of code of four well-known numbers - the answer is not so much a total of 24 combinations, one of them needs work, so go ahead pick up code.

The main thing is to find all the numbers yourself, otherwise the award will be unexpected...)

ashleyalicia
No, not generates. Because the code 3165 and not 1365

ashleyalicia
It cannot be different, because there are only 2 codes 3165 and 1365
On the light of 1365 and from the middle and above"3165

ImGabeNewell
what are you reading and do not understand what you write or are you a game developer, I have these two codes did not work, tebezh it said in pure Russian that code can be different 24 option, even on many guides already written that 3165 and 1365 are most common BUT may not be suitable then iterate through all 24 not work

ashleyalicia
SPS friend,began to go through all 24 variations of the codes written on the rise and only the fourth column in my sheet worked.came code 6513
Spoiler

If I'm not mistaken that is a four - digit combination in which any of the fields may be any of the 4 numbers has 4 in the 4th degree options, that is 256 and not 24))

Shyrik408
wrong,he just write by hand on the rise))

Spoiler

Ga M eR
Mmm... no, I'm not mistaken) There is a four-digit code with no repetition of symbols in each order(i.e. no 1111, 3333, etc), possible numbers have 1, 3, 5 and 6, i.e. their 4D). This implies that each order can be located any one of these figures, as well as their four - it's all multiplied by 4re. Result 4 in converteu extent, QED as they say;)

Shyrik408
well, I'm on a leaf painted all combinations of different (not identical) numbers.see ,logically you're right,but you're right in the case where are involved all the numbers from 0 to 9 but in this case involved only 4 numbers, namely 1,3,5,and 6 respectively and 4 digits maximum possible pure combinations (differently) is 24.

Ga M eR
Sorry, my bad). I counted with repetitions, ie, 1113, 1115, 1116, etc.)
Considered simple according to the formula of combinations (which take into account repetition), i.e.
The first digit can be choose 4 is 4 version.

For each of these 4 choices the second digit can be chosen too 4 means 4*4 = 16 variants.

For each of these 16 variants of the third figure, you can choose again, 4 is 16*4 = 64 possibilities.

For each of these 64 options for the fourth digit you can select all the same 4 is 64*4 = 256 options.

Shyrik408
here found the answer on the responses of ru
Spoilersi we are talking about four-digit combination of decimal digits, such combinations (of numbers) 9999, and with the combination 0000 - all 10000.
But if we are talking about the number of permutations of four some recurring characters, such combinations only 24.
for example, signs 1234 you have 24 ways :
1234
1243
1324
1342
1423
1432
2134
2143
2341
2314
2413
2431
3124
3142
3214
3241
3412
3421
4123
4132
4213
4231
4312
4321

Ga M eR
To catch up I had to paint all the numbers. Well... nothing, but contrived for the week ahead. Now again, you can become a bellend)

Ga M eR
Shyrik408
there is an easier way to find the number of combinations))) how many options in the first stage, 4 figures, second 3, third 2, last 1 TOTAL pereemnaya consistently 4х3х2х1= 24 and if I was involved in all the figures we get 10х10х10х10=10000

Thomas Freeze
now dare to touch this code...
WORKED damn first 1356

but these cards to learn something?? tell me guys, pleeezzzz!!!!!

Tomas Freeze
SAP